Question

Could someone help me with:

Suppose sin(β) = 1/7
Find the exact value of sec(β) for 0 < β < pi/2

Thanks in advance!

Answer 1

@Rhope we know sec x = 1/cos x
could you find cos x?

Answer 2

my draw function isnt working so i'll need to do this another way

relation between sin B and cos B is
cos^2 B = 1 - sin^2 B
= 1 - (1/7)^2
so cos B = sqrt(1 - 1/49)

= sqrt 48/49
now sec B = 1/ cos B
so sec B =sqrt ( 49 / 48)

which we can simplify further

Answer 3

sec B = 7 / sqrt 48
= 7 / 4sqrt3
= 7sqrt3 / 4

Answer 4

I figured it out using the triangle and SOHCAHTOA. Thanks though everyone! (:

Answer 5

good - thats the way i was going to show you if my draw thing was working!