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Mathematics 14 Online
OpenStudy (anonymous):

I have the hardest time writing new equations for this graph

OpenStudy (anonymous):

OpenStudy (anonymous):

lets do the blue one

OpenStudy (anonymous):

\(y=-x^2\) has vertex at \((0,0)\) and this one has vertex at \((1,4)\) so it is shifted to the right 1 unit and up 4 units. therefore the equation is \(y=-(x-1)^2+4\)

OpenStudy (anonymous):

if that answer is not what you are looking for, you can do some algebra to put it in standard form \[y=-(x-1)^2+4=-(x^2-2x+1)+4\] \[=-x^2+2x-1+4=-x^2+2x+3\]

OpenStudy (anonymous):

others are similar, hope steps are clear

OpenStudy (anonymous):

the first one is what i'm looking for. Thank you

OpenStudy (anonymous):

yw

OpenStudy (anonymous):

so is the red -(x+2)^2 + 3?

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