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OpenStudy (anonymous):
Solve for x
\[\frac{ x }{ (x+1)(x-2) }=1\]
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OpenStudy (lgbasallote):
simplify your denominator first
\[\implies \frac{x}{x^2 + x - 2x - 2} = 1\]
simplify...
\[\implies \frac{x}{x^2 - x - 2} = 1\]
right?
OpenStudy (anonymous):
ok, I thought it was already simplified?
OpenStudy (lgbasallote):
by simplify i meant expand
OpenStudy (anonymous):
right. please continue.
OpenStudy (lgbasallote):
now cross multiply
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Parth (parthkohli):
You could also have started with\[x = (x + 1)(x - 2)\]\[ x = x^2 - x - 2\]\[ x^ 2 - 2x - 2 = 0\]This is a quadratic equation.
OpenStudy (lgbasallote):
what do you get if you cross multiply \[\frac{x}{x^2 - x - 2} = 1\]
?
OpenStudy (anonymous):
oh I get it.
OpenStudy (anonymous):
cheers guys.
Parth (parthkohli):
@Hollywood_chrissy Lord LG tells you to multiply \(x^2 - x - 2\) to both sides.
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Parth (parthkohli):
G'job
OpenStudy (lgbasallote):
if G'job means good job... does that mean B'job means bad job?
Parth (parthkohli):
...
Parth (parthkohli):
@lgbasallote you're very punny.
OpenStudy (lgbasallote):
you'll understand when you're older
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Parth (parthkohli):
I know what b'job is.
OpenStudy (zzr0ck3r):
lol
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