Mathematics
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OpenStudy (anonymous):
The domain of the given function is {4, -2}. What is the range?
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OpenStudy (anonymous):
h (x) = 2x^2 - 5
Parth (parthkohli):
You plug-in 4 and -2 in the function respectively.
Parth (parthkohli):
Essentially, you have to find \(h(4)\) and \(h(-2)\).
Parth (parthkohli):
Can you do that?
OpenStudy (anonymous):
ooo ok let me try
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Parth (parthkohli):
Sure
OpenStudy (anonymous):
h(4) = 2(4) and does h (-2) = 2(-2)
Parth (parthkohli):
No...
Parth (parthkohli):
\[ h(4) = 2(4)^2 - 5\\h(-2) = 2(-2)^2 - 5\]
OpenStudy (anonymous):
o ok
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OpenStudy (anonymous):
so now i have to multiply these or solve i mean
OpenStudy (anonymous):
is the final answer
(-13, 11)
OpenStudy (anonymous):
hello?
Parth (parthkohli):
Nope, not.
OpenStudy (anonymous):
how come?
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OpenStudy (anonymous):
i did the work and thats what i found out though
OpenStudy (anonymous):
or maybe i did it wrong
Parth (parthkohli):
\[h(4) =2(4)^2 - 5 \implies 2(16) - 5 \implies 32 - 5 = 27 \]
OpenStudy (anonymous):
ooooooooooo ok
OpenStudy (anonymous):
i got my answer now, is it 3,27
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Parth (parthkohli):
No!
Parth (parthkohli):
You got the 3 and 27 part right, but since the domain is {4,-2}, we have {27,3} as the range.
OpenStudy (anonymous):
o ok i get it thnx
Parth (parthkohli):
You're welcome! And were you born in 1999 too?
OpenStudy (anonymous):
yes...
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Parth (parthkohli):
Me too :)
OpenStudy (anonymous):
nice!
OpenStudy (anonymous):
can u help me with one more question?
OpenStudy (anonymous):
18 - 8x - 15 = -7 - 5 ( x - 1) + 5
OpenStudy (anonymous):
i got the answer -5x = 7
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Parth (parthkohli):
Can you post it after closing this one?
OpenStudy (anonymous):
sure