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Mathematics 22 Online
OpenStudy (anonymous):

if pa=10 and be=21 find bp

OpenStudy (anonymous):

Is there a diagram to go with this information?

OpenStudy (anonymous):

OpenStudy (anonymous):

Thank you. Can we assume AP is tangent to the circle and that BE is a diameter?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

Well, first thing that comes to mind (because I can't remember the tangent-chord theorems off the top of my head right now..) is that you can form a right triangle AOP with O the center of the circle and AO a radius. From there you can use Pythagoras' theorem to get the missing lengths.

OpenStudy (anonymous):

It's not very direct, but will work.

OpenStudy (anonymous):

How can AOP form a right triangle? I drew the line(auxillary lines) and it appears acute.

OpenStudy (anonymous):

Angle AOP being acute.

OpenStudy (anonymous):

Yes. Angle OAP is the right angle because tangents to a circle are always at right angles to their radii.

OpenStudy (anonymous):

Oh yeah...

OpenStudy (anonymous):

I think that's the preliminary proposition that is used to prove the various tangent and chord theorems. I like this website for reviewing such things: http://www.mathwarehouse.com/geometry/circle/tangent-secant-side-length.php

OpenStudy (anonymous):

OA=10.5 correct?

OpenStudy (anonymous):

Line OEP is therefore the hypotenuse, and when you add OB=OA, you get BP. Yes, OA is a radius so is half the diameter BE.

OpenStudy (anonymous):

Oh, that's nice, everything works out to rational numbers. Very kind of them . . .

OpenStudy (anonymous):

|dw:1346780775442:dw|

OpenStudy (anonymous):

I'm still not sure how to find EP?

OpenStudy (anonymous):

I don't think you need EP, but did you use Pythagoras' theorem to get OP?

OpenStudy (anonymous):

10(^2)+10.5(^2)=c(^2) I get 210.25???

OpenStudy (anonymous):

I was going to find EP. Then add BE+EP=BP

OpenStudy (anonymous):

(take square root of c^2)

OpenStudy (anonymous):

Ahhh. 14.5 + 10.5 correct? Equaling 25

OpenStudy (anonymous):

If you use the theorem from that website I linked to, it shows the following: |dw:1346781296754:dw| Which when you simplify and put into standard form yields the quadratic equation x^2+21x-100=0. I find that unnecessary if you don't like quadratics. Either way it includes an extra step and Pythagoras' theorem gets us there just as easily.

OpenStudy (anonymous):

Yes, the solutions to that quadratic equation are x=4 and x=-25. Throw out the negative length as meaningless, and EP=4; add that to the diameter and BP=25.

OpenStudy (anonymous):

Okay good. Sometimes I just need someone to make me ask myself the right questions.

OpenStudy (anonymous):

Thanks for helping! I have another if you don't mind...?

OpenStudy (anonymous):

I usually never bother to remember such specific theorems, I prefer to deduce everything from more basic stuff that is easy to remember.

OpenStudy (anonymous):

Sure, I got time.

OpenStudy (anonymous):

Yes, and the PT is very easy.

OpenStudy (anonymous):

Exactly, it shows up everywhere; only thing you had to remember is that tangents are perpendicular to radii.

OpenStudy (anonymous):

Exactly.

OpenStudy (anonymous):

Might as well start a new thread for your next question; maybe we can get others to jump in and add their insights as well.

OpenStudy (anonymous):

Will do.

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