Question

\[\int\limits dt\]Doesn't this end up becoming\[ \int \limits 1dt\]which in turn becomes\[t + c \]?

Answer 1

That's my interpretation.

Answer 2

Yes, it could, in some sense or another. It depends on the degree of your 'abuse of notation' (as it's called). i.e. if you represent \(dt\) as a multiplicative quantity, then you would be right, or, if you represent it as an operator, then it'd be simply \(C\), not \(t+C\).

Answer 3

Thank you!