Question

integrate 3u^2du/(1+u) from 0 to 1

Answer 1

\[\int_{0}^{1} {3u^2du \over 1 + u}\]Is that the question?

Answer 2

yes

Answer 3

OK, can you first perform the indefinite integration?

Answer 4

Im having trouble setting that up

Answer 5

I dont see how to break it into partial fractions

Answer 6

I have to go to sleep, sorry for the inconvenience... :(

Answer 7

3u² = 3 ( u² - 1 + 1 )
= 3 ( u -1) ( u+1) + 3

Answer 8

-> 3 ( u -1 ) + 3 / ( u +1)

Answer 9

Yes! You can do long division since the degree on top is greater than or equal to the degree of the polynomial on the bottom.
Or do what @Chlorophyll did which is a really really cute way.

Answer 10

@myininaya Thanks for nice compliment. It's actually the lazy way :")