Question

i need a hero !!! What is the sum of a 22–term arithmetic sequence where the first term is 55 and the last term is –29?

Answer 1

too bad @Hero is offline

Answer 2

just my luck -___-

Answer 3

sorry couldn't resist saying ti

Answer 4

it*

Answer 5

No hero here, but I can give an answer?
We know the average of the series is:
\[
\frac{55+(-29)}{2}
\]And the number of terms is \(22\), so, we simply state:
\[
22\frac{55+(-29)}{2}=11(55+(-29))=11\cdot 26=286
\]And we are done.

Answer 6

@lgbasallote You're on a roll, today XD

Answer 7

whoops ... i meant to ask this quesion .. lol im dumb .. (What is the 15th term of the arithmetic sequence 18, 25, 32, …)

Answer 8

D: Nooo, what the hell did I do?

Oh, all right

Answer 9

It's an arithmetic sequence, so what's the common difference?

Answer 10

lol yeahh im sorry, im not completely focused im just trying tto get this done so i dont have to do it tomorrow when im in NY dealing with my grandpas funeral and stuff

Answer 11

oh i'm so sorry...

Answer 12

notice how 25 - 18 = 7 and how 32 - 25 = 7

So the common difference is 7

So d = 7

Answer 13

The first term is 18, so a1 = 18

Answer 14

You use these two pieces of info to find the nth term

an = a1 + (n-1)*d

an = 18 + (n-1)*7

an = 18 + 7n - 7

an = 7n - 11

with me so far?

Answer 15

you completely lost me, but im not trying to learn right now i just need to finish , and its not your fault at all it was his time he was 86

Answer 16

he lived a good live , a real man among men ♥

Answer 17

life*