is it possible for a rectangle with the perimeter of 52 cm to have an area of 148.75 cm?

Question

anonymous · Answer

Yes.

anonymous · Answer

why?

anonymous · Answer

Just kidding. Let's see...

anonymous · Answer

Perimeter = 2A+2B
Area = A*B

52=2A+2B
148.75=A*B

52-2A=2B
(52-2A) / 2 = B

148.75 = A * ((52-2A)/2)
$$148.75 = A  (\frac{ 52-2A }{ 2 })$$
so......

anonymous · Answer

$$\frac{ 148.75 \times 2 }{ A } = 52 -2A$$

anonymous · Answer

(we can do that because it's a rectangle so A it's not zero)

anonymous · Answer

Gosh I got lost. Not sure :(

anonymous · Answer

im at a COMPLETE loss lol but thanks

lgbasallote · Answer

anything is possible actually

anonymous · Answer

so what exactly could i put as the answer then?

lgbasallote · Answer

you continue what hookdump was doing

$$148.75 = A(\frac{52 - 2A}{2})$$
$$\implies 148.75 = A(26 - A)$$
$$\implies 148.75 = 26A - A^2$$
change to quadratic form

$$\implies A^2 - 26A + 148.75 = 0$$
use quadratic formula to solve for A

anonymous · Answer

ok........ whats your answer? this looks wrong (my answer)