Determine where f(x)= (x-x^2) / (1+8x^2) is increasing and decreasing.
did you find f'(x) ?
Yes I did
Not sure about the increasing part though
cool you can look at where it is positive and negative... where it is positive, f(x) is increasing... where it is negative f(x) is decreasing
Can you give an example ?
I have f'(x)
I'd recommend you plot it, the numbers look a little rough to be doing algebra, but just as a rough sketch... the denom. is always positive so... look at the numerator...
-8*x^2 -2*x +1
that's going to be negative for most x; the only time it will be positive is when 1> 8*x^2 +2*x
ie for small values of x ... you could actually solve that for the roots.... and then you'd know where it will be positive... because you have already determined that it will look something like:|dw:1346810367241:dw| (roughly)
is that clear?
So it is possible to do it algebraically though right? With f'(x)
I'm looking it over... seems messy, so I'm guessing they want you to do it with a calc. ...?
Yeah I just plugged it in
|dw:1346810711456:dw|
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