Question

Continued fractions ...

Answer 1

a continued fraction can be constructed by taking subsequent recpiricals

Answer 2

\[\frac pq=\frac{1}{q/p}\]
i was wondering how they got it for like sqrt(2)

Answer 3

yes, like that

Answer 4

is this a tutorial or a question?

Answer 5

\[\sqrt{2}=1+(\sqrt{2}-1)=1+\cfrac{1}{\frac{1}{\sqrt{2}-1}}\]
\[1+\cfrac{1}{\frac{1}{\sqrt{2}-1}*\frac{\sqrt{2}+1}{\sqrt{2}+1}}=1+\cfrac{1}{\frac{\sqrt{2}+1}{2-1}}\]
a little of both

Answer 6

i like how the bump timer fakes you out; it shows the button but says you cant when you hit it lol

Answer 7

lol that happens with me sometimes

Answer 8

how do we find the continued fraction of pi?

Answer 9

not that these things are unique, but i still have to wonder

Answer 10

hmn for that you will have to wait just for 1 min.. please

Answer 11

1+pi -1 = pi

1 + 1/(1/pi) -1 = pi

correct?

Answer 12

\[\large{1+\pi -1=\pi}\]
\[\large{1+\cfrac{1}{\frac{1}{\pi}}-1=\pi}\]