What is the y−coordinate of the y−intercept of the line that passes through the points (−4, −4) and (4, 8)?
ok so the best thing we can do is to find the equation of this line
can you find the slope of this line ?
how do you find it again??
i havent done this is so long..:/
in*
ok so slope : m = (y1 - y2) / (x1-x2)
oh oh ok let me try
-4-8=-12 and -4-4=-8 so -12over-8?
yes .. which is 1.5
now.. find line equation by : y = y1 + m(x-x1) (x1,y1) may be one of your two points that you got
wait what? :P
y = y1 + m(x-x1) -> if you use this formula you can get the line equation in our case we can choose x1 = -4 , y1 = -4 or x1= 4 ,y1 = 8
so the anwser is 4,8?
or wait? yah no...im lost..im sorry :(
ok again .. we need to find y intercept
its the point where x=0 right ?
i thnk soo yes
so what i want to do is to find the equation of the line what it means is that in this equation i will be able to plug x =0 and get the y-intercept or any other x that i want to find the corresponding y of it
we already found the slop of this line m = 1.5
yes
now if you have a point that the line passes through and you got also the slope of the line you could find the equation that describes the line using this formula : y = y1 + m(x-x1) where m - slope (x1,y1) a point that the line passes through
oh ok so it could be y=8+1.5(4+4) ?
?
why ? look at the formula 1.5(x-x1) so y=8+1.5(x-4)
do you understand why ? x for us is anything we want in this case we would like to plug x=0 since we want y intercept
okk
now y=8+1.5(x-4) this is our line equation replace x by 0 and you will get y intercept .. do you understand what we have done ?
yes i think so..so y=8+1.5(0)-6 ?
yes y intercept would be 2
ohhhhhh thats the anwser!! :) thank you! can you help me with a few more??
yes but you must understand .. try to do it by your self and tell me where you stuck
okay the questions i put up here i dont understand..:P let me tryyy
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