Question

Assuming x ≠ 0 and y ≠ 0, what is the quotient of

Answer 1

\[\frac{ 12x ^{6} y ^{2}+8x ^{4}y ^{3}+4x ^{2}y ^{4}}{ 4x ^{2}y }\]

Answer 2

i think you can factor 4x^2y in numerator, then the denominator cancels compeltely... try..

Answer 3

um how do you factor again?

Answer 4

numerator : 4 is common in all terms, right ?

Answer 5

yes ithink so

Answer 6

\(12x^6y^2+8x^4y^3+4x^2y^4\)

Answer 7

= \(4(3x^6y^2+2x^4y^3+x^2y^4)\)

Answer 8

right ?

Answer 9

yes? :)

Answer 10

\(4y(x^6y+8x^4y^2+4x^2y^3)\)

Answer 11

\(4x^2y(x^4y+8x^2y^2+4y^3)\)

Answer 12

does that make sense how we factored 4x^2y ?

Answer 13

i think so..:P yes

Answer 14

great !

so,

\(\huge \frac{ 12x ^{6} y ^{2}+8x ^{4}y ^{3}+4x ^{2}y ^{4}}{ 4x ^{2}y } \)

= \(\huge \frac{4x^2y(3x^4y + 2x^2y^2 + y^3)}{4x^2y} \)

= \(\huge \frac{\cancel{4x^2y}(3x^4y + 2x^2y^2 + y^3)}{\cancel{4x^2y}} \)

= \(\huge 3x^4y + 2x^2y^2 + y^3\)

Answer 15

does that help/make sense @luvbouncer11

Answer 16

yes :) thanks