Question

x^2 13 years ago

Answer 1

best bet is to start with \(x^2-x-6<0\) and solve that one by factoring

Answer 2

\[(x-3)(x+2)<0\] and since this is a quadratic it is a parabola that faces up, will be negative between the zeros and positive outside of them
the zeros are \(-2\) and \(3\) so it is negative between those two numbers

Answer 3

ok thankyou