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OpenStudy (beth12345):
\[\frac{ x }{ 3 } + \frac{ 1 }{ x-2 } = 2\] i find it easier to understand when its written in this form
OpenStudy (campbell_st):
multiply each term by 3(x-2) this will eliminate the fraction
which will give
\[x(x-2) + 3 = 2 \times 3(x-2)\]
next you need to expand and simplify.
Write the equation will all terms on the left and equal to zero.
Then you need to solve the resulting quadratic
OpenStudy (beth12345):
how do i get both sides to be multiplied by x-2?
OpenStudy (beth12345):
like wouldn't it cancel out?
OpenStudy (campbell_st):
(x - 2) is the denominator of the 2nd term. the common denominator is 3(x-2)
by multiplying by the common denominator you eliminate all denominators
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OpenStudy (beth12345):
ok
OpenStudy (beth12345):
so would it become x+1=2X3(x-2) ?
OpenStudy (beth12345):
\[x+1=2\times 3(x-2)\]
OpenStudy (beth12345):
oh ok nvm, i see how you did that
OpenStudy (beth12345):
i was multiplying everything on the left as one term
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