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Mathematics 13 Online
OpenStudy (anonymous):

4/(x-4)^2=1

OpenStudy (lgbasallote):

\[\huge \frac 4{(x-4)^2} = 1\] cross multiply first...what do you get?

OpenStudy (anonymous):

\[4=(x-4)^2\]

OpenStudy (lgbasallote):

right. now take the square root of both sides

OpenStudy (anonymous):

Got it, x=6?

OpenStudy (lgbasallote):

hmm not quite...remember \[\sqrt 4 \implies \pm 2\]

OpenStudy (lgbasallote):

so you need to have TWO values..make sense?

OpenStudy (lgbasallote):

x = 6 is right. However, it's just one of the two. what's the other?

OpenStudy (anonymous):

x=-6

OpenStudy (lgbasallote):

no.. \[4 = (x-4)^2\] if you take the square root of both sides you have \[\pm 2 = x - 4\] so.. solve for x in \[x-4 = 2\] AND \[x - 4 = -2\] got it?

OpenStudy (anonymous):

OH. So, x= 6; 2. THANKS!

OpenStudy (lgbasallote):

right. good job

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