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Physics 20 Online
OpenStudy (anonymous):

A brick falling freely from a helicopter drops 40 meters during a certain 1-second time interval. The distance it will fall in the next second is A. 56 B. 45 C. 80 D. 50

OpenStudy (shivaniits):

but if we take account of the distance it has travelled in 1 sec it would define its velocity..i.e if its travelling 40 m in 1 sec then its initial velocity could be taken as u=40m/s \[a=10m/s ^{2}\] t=1 sec then acc to relation \[s=ut+1/2at ^{2}\] we would get \[s=40(1)+1/2\times10(1)^{2}=40+5=45m\]

OpenStudy (shivaniits):

that's why i am considering the initial velocity u to be 40m/s as v is changing wrt to acceleration(gravity) at 10m/s^2..and measuring the distance regarding it!!

OpenStudy (shivaniits):

i have considered v as final velocity that depend on time duration at which we are supposed to calculate it..

OpenStudy (shivaniits):

i have not considered the average velocity i have only considered the initial velocity that we require in the relation \[s=ut+1/2at ^{2}\] where u=initial velocity

OpenStudy (shivaniits):

so are we here looking for the distance in nth second or n seconds..??

OpenStudy (shane_b):

I finally get what you're saying. Yes, the answer is 50m.

OpenStudy (shivaniits):

i got it the answer is 50...!!..thanks @demitris

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