Question

Prove that--log with base value of 10
log 2 +16 log 16/15 + 12 log 24/25 +7log81/80
=0

Answer 1

use the rule
\[\log_{}(a/b)=\log_{}a-\log_{}b \]

Answer 2

\[\log_{}2 +16[\log_{}16-\log_{}15 ]+12[\log_{}24-\log_{}25 ]+7[\log_{}81-\log_{}80 ]\]
\[\log_{} 2+16\log_{}16-16\log_{}15 +12\log_{}24-12\log_{}25 +7\log_{}81-7\log_{}80 \]