Question

Does -1/2m(4m^2-2mn)=-2m^3+m^2n?

Answer 1

is that \[\huge -\frac 1{2m} (4m^2 - 2mn)= -2m^3 + m^2n\]

Answer 2

yes except the m isnt in the denominator

Answer 3

ooh...well then
\[\huge -\frac 12 m ( 4m^2 - 2mn)\]
distribute
\[\huge \implies -\frac{4m^2 \times m}2 - \frac{-2mn \times m}2\]
multiply..
\[\huge \implies -2m^3 + m^2 n\]
so yeah you're right

Answer 4

ok thanks

Answer 5

welcome

Answer 6

lol thanks