Question

What is the vertex of this quadratic function?

f(x) = 2(x – 3)^2 – 5

Answer 1

i think you wrote that wrong...check again

Answer 2

yes :) thankyou

Answer 3

\[f(x)=2(x-3)^2-5\implies f(x)=2x^2-12x+13\]
now use \[x={-b\over2a}\]and solve:\[x={12\over2(2)}\]
so you should end up with the vertex as \[x=3\]

Answer 4

Wait what?!

Answer 5

what?

Answer 6

f(x) = 2(x – 3)^2 – 5

This is already in vertex form.

a(x-h)^2 + k

where (h,k) is the turning point.

Answer 7

Therefore:
vertex = (3, -5)

Answer 8

^or that...that is fine also

Answer 9

Like i said..

Answer 10

haan haan zyada free na ho -.-

Answer 11

Mujhay yummydummy nay thori na kata k main free honga. :P :D

Answer 12

^iska kya matlab??? :P
meray kaatnay se free kyun?? LOL

Answer 13

lol, acha hua samajh nahi aaya.

Answer 14

nahi nahi samjhao naa...kehtay kya ho?? :P

Answer 15

http://nooooooooooooooo.com/

Answer 16

LOLOLOL