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Use the Binomial Theorem to expand the binomial. (x + 2y^2)^3 A. x^3 - 3x^2y^2 + 3xy^4 - y^6 B. x^3 + 6x^2y^2 + 12xy^4 + 8y^6 C. x^3 - 6x^2y^2 + 12xy^4 - 8y^6 D. x^3 + 3x^2y^2 + 3xy^4 + y^6
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We have: \[ (x+2y^2)^3 \]With coefficients \(\{1, 3, 3, 1\}\), which is: \[ 1x^3+3(x^2)(2y^2)+3(x)(2y^2)^2+1(2y^2)^3=(x+2y^2)^3 \]Use that to finish your problem.
B?
Yep.
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