Question

the derivative of \(v = 5.00t^2 + 4.00t\) is 10t + 4 yes?

Answer 1

nods

Answer 2

almost afraid to answer...

Answer 3

yes it is.

Answer 4

so tell me...

The speed of an object is given by v = 5.00t^2 + 4.00t where v is in m/s and t is in s. What is the acceleration of the object at t = 2s?

how come this is 20 m/s?

shouldn't it be 14?

Answer 5

24*

Answer 6

10

Answer 7

becuase \[v' = 10t + 4\]
\[v'(2) = 10(2) + 4 \implies 24\]

Answer 8

oh wait thats the velocity equation

Answer 9

yeah...

Answer 10

It should indeed be 24.

Answer 11

must be 24

Answer 12

why is it suppose to be 14?

Answer 13

for some reason..20 is the answer...and even more weird.. I got it right when I answered it then

Answer 14

could it be a matter of rounding off?

Answer 15

nvm it was a typo

Answer 16

sig figs?

Answer 17

Nope, I think your textbook or whatever is just wrong. I don't see why you would want an answer to one significant figure in classical mechanics!

Answer 18

well the instruction is to choose the best answer. If the answer is not in the choices, pick e which means none of the above

then the choices were 5,9, 10, 20

Answer 19

Then 20 is closest so just choose that, but kick up a fuss with your lecturer/teacher :P

Answer 20

lol

Answer 21

Tell him that Einstein would be disgusted at the disgraceful and needless loss of accuracy, so you refuse to answer the question as a protest. :D

Answer 22

the acceleration of the object is
always\[a(t)=v \prime(t)=d \prime \prime(t)\]
a=10

Answer 23

this is velocity equation

Answer 24

distance changes quadraticly,i am hoping that formular is likely distance

Answer 25

@Jonask makes a good point. If the equation you gave us is actually the one for distance then the answer would indeed be 10.