I need help
the polynomial 8x^3 - 343y^3 can be factored into the product of two polynomial, A*B where the degree of A is greater than the degree of B Find A and B

Question

I need help
the polynomial 8x^3 - 343y^3 can be factored into the product of two polynomial, A*B where the degree of A is greater than the degree of B Find A and B

anonymous · Answer

turns out $343=7^3$ so you have $$(2x)^3-(7y)^3$$ which is the "difference of two cubes"

anonymous · Answer

factor difference of two cubes as 
$$a^3-b^3=(a-b)(a^2+ab+b^2)$$ in your case $a=2x$ and $b=7y$

anonymous · Answer

i got this (2x-7y)(2x^3+2x*7y+7y^3)

phi · Answer

look more carefully at sat's equation:
if a= 2x  and the equation has a^2 (which means a*a), then you want 2*x*2*x= 4x^2
or (2x)^2= 2^2*x^2= 4x^2
also, the middle erm 2*x*7*y can be simplified a bit:  2*7*x*y or 14xy
and you must fix the last term b^2 with b=7y