The length of a rectangle is 3mm more than twice its width, and the area of the rectangle is 77mm^2 . Find the dimensions of the rectangle.

Question

anonymous · Answer

length = l
width   = w

l=2w+3

area = l*w

$$lw=2w^{2}+3w$$

but area is 77

$$77=2w^{2}+3w$$

pradipgr817 · Answer

length x (2 x length +3) = 77
sole it

anonymous · Answer

sole the quadratic equation find possible value of w and substitute that value in other equation to get l

anonymous · Answer

solve*

anonymous · Answer

im lost sorry, this is not my thing

anonymous · Answer

let length be L,width be W 

|dw:1347032177913:dw|

it is give that length is 3mm more than twice the width.....

think like this...

twice the width is .......2W

3mm more than twice the width is .......3+2W

3mm more than twice the width IS LENGTH ......L

so 
L=3+2W..


but AREA= length * width=L*W

but we got L = 3+2W

so AREA = (3+2W)*W...expand it

area is give as 77

77= 3W+2W^2

$$77=3W+2W^{2}$$