graph y = -|x + 1|;
when does x+1 = 0 ?
not sure?
im going to have to ask why ....
Oh why graph?
no why dont you know how to solve: x+1 = 0
Online school, they don't go over things
ok, then what about the equation do you not understand
just how to find the answer and how to graph it.
if you cant figure out how to do: x+1=0 then you definantly are not ready to graph anything. and you obviously have no useable input to even help out in a solution ... i wouldnt even know where to begin
x+1 = 0 when x = -1 because -1 + 1 = 0 since we plug in x = -1 then it will turn to 0
well this was the question: On a separate piece of graph paper, graph y = -|x + 1|; then click on the graph until the correct one appears.: it gives you different graphs to chose from.
do you know the basic shape that you are looking for at least?
It's like this, but the options move from small to large
well we know for a fact that absolute value of anything will be like this |dw:1347046996746:dw|
good, we are looking for an upside down V that is "pointing" to x = -1; since: -1+1 = 0 satisfies the equation: x+1=0
you just gave a picture of an upside down V to us .....
wait....so I am basically just looking for the line of the number where the point sits on?
adunb, that +1 is inside the function and is controling the "x" (side to side)
y = |x| + 1 ; controls the y
oops i was looking at the wrong one yea it controls the side to side sorry
|dw:1347047249530:dw|
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