Write a quadratic equation in standard form that has two solutions, 1 and -6 ___?_=0 (the leading coefficent must be 1 )

Question

Write a quadratic equation in standard form that has two solutions, 1 and -6 ___?_=0  (the leading coefficent must be 1 )

anonymous · Answer

if those are the solutions, can you write the expression in factored form?  
{Where and how do the solutions show up in the factored form of a quadratic?}

anonymous · Answer

I'm not really sure how to do that?

anonymous · Answer

factored form is like   (x + ___)(x + ___) =0
remember?

anonymous · Answer

so it would be x+6 and x+1 right

anonymous · Answer

what usually goes in the blanks?

anonymous · Answer

(x+6)(x-1) =0

anonymous · Answer

I'm confused sorry.

anonymous · Answer

they give you the solutions.   Remember what 'solution' means: it's the value of x that makes an equation true....     if one of the solutions is -6    does putting -6 in for x make the expression I just showed you true?

anonymous · Answer

yes?

anonymous · Answer

right.

anonymous · Answer

so do you agree that  (x+6)(x-1) =0  is the factored form of the quadratic with solutions of -6 and 1?

anonymous · Answer

yes

anonymous · Answer

the computer said that was wrong??

anonymous · Answer

it's the factored form, expand it to get the standard form.

anonymous · Answer

so would the answer be x^2+5x+6??

anonymous · Answer

yep