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Mathematics 22 Online
OpenStudy (anonymous):

lim (absolute value (x))/(x) as x-->(-2)

OpenStudy (anonymous):

Try direct substitution.

OpenStudy (anonymous):

OpenStudy (anonymous):

Here is some of my work. I get two different answers, (-1) and 1.

OpenStudy (anonymous):

BUt apparently the answer is only (-1). What is incorrect in what I did?

OpenStudy (anonymous):

|x| is always positive.

OpenStudy (anonymous):

-1 is the answer

OpenStudy (anonymous):

|x| = -x is never true.

OpenStudy (anonymous):

It's a positive divided by a negative, so the answer has to be negative.

OpenStudy (helder_edwin):

when \(x\to-2+\) the variable \(x\) is negative. so \[ \large \lim_{x\to-2+}\frac{|x|}{x}=\lim_{x\to-2+}\frac{-x}{x} \]

OpenStudy (anonymous):

Ah, so I'm just plugging in (-2) directly into the absolute value to get positive 2 then. See, I was watching this video( http://www.youtube.com/watch?v=TUPkwGlrT8A), and this guy did the (-x) thing with absolute value of x. It's at about the 1:00 mark. Is he wrong the way he does that?

OpenStudy (helder_edwin):

the only difference with your problem and the u-tube video is that you have \(x\to-2\), i.e., the variable approaches a negative value and the absolute u r given is not symetric with respect to -2. in the video, the absolute value u see is symetric with respect to 1.

OpenStudy (anonymous):

I see. Ok, thanks for the help everyone.

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