Question

completely factor the following expression; 100y^2 -36z^2

Answer 1

note :
\(10^2=100 \quad and \quad6^2 = 36\)
hint: use \(a^2-b^2=(a+b)(a-b)\)
does this help ??

Answer 2

okay i got 4(25y^2-9z^2)

Answer 3

but i think i need to factor 25y^2-9z^2 also but im not sure if it factors anymore

Answer 4

yes,it does. thats step is also the correct first step.
now note 25=5^2 and 9=3^2
so its
(5y)^2-(3z)^2
now can u factorize using a^2-b^2 ?

Answer 5

4(25y^2-9z^2)
and then factor 25y^2-9z^2
= (5y^2)(2)-(3z^2)(3)
is this right

Answer 6

where does (3) come from ?? in the end
and u still need to factorize
we know \(a^2-b^2=(a+b)(a-b)\)
so just put a=5y^2 and b= 3z up there and tell me what u get.

Answer 7

*a=5y

Answer 8

a^2-b^2=(5y+3z)(5y-3z)

Answer 9

are u getting what i wanted to say?

Answer 10

yes is what i just type right

Answer 11

yup thats correct :)
and don't forget 4 in the end
4(5y+3z)(5y-3z)

Answer 12

okay

Answer 13

yes thank you

Answer 14

welcome :)