Question

An arrow is shot at an angle of 45 degree above the horizontal. The arrow hits a tree a horizontal distance D = 220 m away, at the same height above the ground as it was shot. Use g = 9.8m/s^2 for the magnitude of the acceleration due to gravity.

Find the time that the arrow spends in the air.

Suppose someone drops an apple from a vertical distance of 6.0 meters, directly above the point where the arrow hits the tree. How long after the arrow was shot should the apple be dropped, in order for the arrow to pierce the apple as the arrow hits the tree?

Answer 1

were you able to get started?

Answer 2

i know D=Voxt
220=Voxt

Answer 3

yep

Answer 4

going to need two equations here however... how about the equation for the y direction (vertical)

Answer 5

and 0=Vosin45t-(1/2)gt^2

Answer 6

good.

Answer 7

Vo*cos(45) *t =220

Answer 8

two equations two unknowns (Vo and t) eliminate Vo

Answer 9

get a result for t yet?

Answer 10

no idk how

Answer 11

solve: Vo*cos(45) *t =220 for Vo
sub.s into the other equation.
solve for t.