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Mathematics 30 Online
OpenStudy (anonymous):

delete

OpenStudy (anonymous):

@jim_thompson5910 just two more problems that I am stuck on!

jimthompson5910 (jim_thompson5910):

How many coins are you selecting?

jimthompson5910 (jim_thompson5910):

alright, one sec

jimthompson5910 (jim_thompson5910):

Are you sure you can select any number of coins you want? Is it supposed to be 3 or 4?

OpenStudy (anonymous):

I am really sorry! It is suppose to be 3!

jimthompson5910 (jim_thompson5910):

ok one sec

OpenStudy (anonymous):

What?

jimthompson5910 (jim_thompson5910):

hold on

jimthompson5910 (jim_thompson5910):

There are 9 C 3 = 84 different ways to choose 3 coins where the order doesn't matter Now let's count the number of ways to make less than 25 cents. If you select a quarter first, then you are not less than 25. So that's out. The first coin must either be a nickel or a dime. --------------------------------------------------------------------------------------------------------------------------------------- If the first coin is a dime, then here are the following ways to get 25 cents: dime, dime, quarter dime, dime, dime dime, dime, nickel where order doesn't matter The only way to get under 25 cents is to have 2 additional nickels: dime, nickel, nickel There are (5 C 1)*(3 C 2) = 5*3 = 15 ways to get under 25 cents with 3 coins (where the first coin is a dime) --------------------------------------------------------------------------------------------------------------------------------------- If the first coin is a nickel, then the same idea is applied and these choices give you totals under 25 cents: nickel, nickel, dime nickel, nickel, nickel There are (3 C 2)*(5 C 1) + 3 C 3 = 3*5 + 1 = 16 ways to do this. ==================================================================================================================================================================================== Add up the previous counts: 15+16 = 31 So there are 31 ways to add up the coins to get under 25 cents. So there are 84 - 31 = 53 ways to get 3 coins to add to 25 cents or more.

OpenStudy (anonymous):

It is saying that's wrong!!

OpenStudy (mathmate):

That was just an example for choosing 3 coins. We are still waiting to see if the number of coins is specified.

jimthompson5910 (jim_thompson5910):

hmm let me think

OpenStudy (mathmate):

Sorry, you already said that 3 coins are drawn, right?

OpenStudy (anonymous):

8?

OpenStudy (anonymous):

wait, no sorry, thinking..

OpenStudy (mathmate):

There are 10 coins in all. Choose 3 out of 10 is 10C3=120. Subtract those under 15 = 5C1*3C2 we get 105.

OpenStudy (anonymous):

It turns out that the answer is 108, but I have no idea how it is 108

OpenStudy (mathmate):

Oops, subtract NNN as well, so that makes 104, not quite 108.

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