Question

find lim [sin^2(-)/(-)(1+cos(-))]
(-)->0

Answer 1

\[\lim_{x \rightarrow 0} \frac{\sin^2 x}{x(1+\cos x)}\]?

Answer 2

0?

Answer 3

agree.... 0...

Answer 4

but how did u guys get 0

Answer 5

the limit as x->0 for sin(x)/x is equal to 1

its a general rule of thumbs

Answer 6

\[\lim_{x \rightarrow 0}\frac{\sin x}{x}=1\]

\[\lim_{x \rightarrow 0}\frac{\sin^2(x)}{(x)(1+\cos(x))}\]
\[\lim_{x \rightarrow 0}\frac{\sin(x)}{(x)}*\lim_{x \rightarrow 0}\frac{\sin(x)}{(1+\cos(x))}\]
\[1*\lim_{x \rightarrow 0}\frac{\sin(x)}{(1+\cos(x))}\]

sin(0)=0
cos(0)=1

Answer 7

oh thanks. :)