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Mathematics 11 Online
OpenStudy (anonymous):

hey i'm intrigued by a circuit analysis question which my prof challenged me with.. can any body help me solve it?

OpenStudy (arlen):

is this your question?

OpenStudy (anonymous):

i'm attaching a jpeg of the circuit

OpenStudy (pradipgr817):

what u need to find in the circuit?

OpenStudy (anonymous):

the node voltage labeled v

OpenStudy (anonymous):

Do you know Kirchoff's laws?

OpenStudy (anonymous):

yes i do.. i tried kvl, kcl, power conservation principle everything.. and yet i can't find v

OpenStudy (anonymous):

What's the voltage on that power source? I can't quite make it out: 10V, 15V?

OpenStudy (anonymous):

10v

OpenStudy (arlen):

10V

OpenStudy (arlen):

one fundamental hint....you don't need to solve....it can be done orally just by analysis and viewing circuit :)

OpenStudy (anonymous):

And what's that over on the right side? is that a 2 ohm resistor?

OpenStudy (anonymous):

yes it is a 2 ohm res

OpenStudy (arlen):

@jayantb1019 one more hint....there is no current in 3 ohm resistor....can you guess how? :)

OpenStudy (arlen):

@jayantb1019 ??

OpenStudy (anonymous):

i got it as 7/6 A anticlockwise in 3 ohm

OpenStudy (arlen):

no

OpenStudy (arlen):

see sume of 4 ampere and 3 ampere is 7 ampere...which is given in the circuit ...so no current flows in 3 ohm arm....look at the circuit again :)

OpenStudy (anonymous):

Are you sure that makes sense? What is the total equivalent resistance for the circuit and how much current is flowing back into the power source?

OpenStudy (anonymous):

there's a 10v voltage source also supplying current, assume current in 3 ohm as x, deduce currents in the peripheral branches using kcl and apply kvl to the outer loop. it turns out to be 7/6 A in 3 ohms

OpenStudy (arlen):

well....i am still confident at my answer....there is no need to calculate ...you guys can find answer just by analysis of it...

OpenStudy (anonymous):

hey i need the voltage v, not the current through 3 ohms res

OpenStudy (arlen):

yes exactly....so eliminate that arm...your calculation or analysis would be easier

OpenStudy (anonymous):

guess wat i cant find the equivalent resistance of the circuit!!!! it seems impossible

OpenStudy (anonymous):

Do have a way to find total current and do individual voltage drops across each resistor?

OpenStudy (anonymous):

yes kcl and kvl, i already did that

OpenStudy (anonymous):

i'm posting a text file which has the currents across each resistor and how i obtained it

OpenStudy (pradipgr817):

consider left node as v1 and right node as v2 then apply kcl

OpenStudy (anonymous):

hey dint get you

OpenStudy (pradipgr817):

left most and right most nodes apply kcl at them, dont assume any x just take direction of currents

OpenStudy (anonymous):

ya i got the currents across each resistor already

OpenStudy (anonymous):

hey its coming to zero volts

OpenStudy (anonymous):

thanks everyone for the insights

OpenStudy (pradipgr817):

how?

OpenStudy (anonymous):

take the node with voltage v as the datum node and apply nodal analysis,

OpenStudy (pradipgr817):

ur assuming reference node to a node at which you need to find voltage is is correct

OpenStudy (anonymous):

i'm not sure bt this is wat i got.. if u ve a person whose got more reliable solution, let me no

OpenStudy (anonymous):

i might go offline.. mail me k.. jayantb1019@hotmail.com

OpenStudy (pradipgr817):

ok

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