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Mathematics 15 Online
OpenStudy (anonymous):

Which of the diagrams below represents the contrapositive of the statement, "If it is a triangle, then it has three vertices" A. Figure A B. Figure B (Picture below)

OpenStudy (anonymous):

OpenStudy (anonymous):

any guesses and why you think its the answer?

OpenStudy (anonymous):

I'd say figure A because contrapositive is just the opposite of the saying right?

OpenStudy (anonymous):

@completeidiot

OpenStudy (anonymous):

Contrapositive is logically equivalent (means the same thing) as the original statement.

OpenStudy (anonymous):

Right, so it's figure A? because it says if it's not a triangle than it doesn't have three vertices. And the original says that triangles do have three vertices.

OpenStudy (anonymous):

A is the inverse because all it is doing is negating the premise and conclusion.

OpenStudy (anonymous):

So it's like saying the same thing.

OpenStudy (anonymous):

But in a different way.

OpenStudy (anonymous):

Or I'm wrong?

OpenStudy (anonymous):

This is a little tricky because the original statement is a definition of sorts, so it's biconditional - that means that it is equivalent to its converse, and since the converse and inverse are equivalent, then the inverse and contrapositive will be equivalent.

OpenStudy (anonymous):

correct me if im wrong, wouldnt the contrapositive statement be if it doesnt have 3 vertices, then its not a triangle?

OpenStudy (anonymous):

Here's the symbolic layout. a=premise, b=conclusion Conditional: a-->b Converse: b-->a Inverse: not a --> not b Contrapositive: not b --> not a Conditional = Contrapositive Converse = Inverse If biconditional, then Conditional = Converse, etc.

OpenStudy (anonymous):

Hmmm, am I reading the direction of the sets wrong? I think I am.. oops. The inner circle is the premise and the outer circle is the conclusion.

OpenStudy (anonymous):

Yeah, sorry, you were right. It is A because if you are in the set of things that don't have 3 vertices, then you have to be in the set of things which are not triangles. I didn't consider the overlapping sets consideration enough and was operating just with the symbols.

OpenStudy (anonymous):

Figure B doesn't make sense because it can't be a triangle an not have three vertices, but it's possible for something to have three vertices and not be a triangle.

OpenStudy (anonymous):

Thank you very much for taking the time to explain everything! It has helped me a lot.

OpenStudy (anonymous):

My pleasure. This world could definitely use more logical thinkers!

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