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Find the indefinite intergral: sqrtx+1/(2sqrtx)
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This? \[\int\limits \frac{\sqrt{x+1}}{2\sqrt{x}}dx\]
No... interal of sqaure root of x + (1/(2sqrtx)) \[\int\limits\]
\[\int\limits \sqrt{x} + \frac{1}{2\sqrt{x}}dx \space \space ?\]
yes
Ok, well that's a lot easier then. You can break it up and rewrite it as: \[\int\limits x^{1/2}dx+\frac{1}{2}\int\limits x^{-1/2}dx\]
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Then use power rule.
Ok thanks so much, could you figure out the final answer to check it with mine
i got: \[1/3 \sqrt{x} (2x+3)+C\]
Sure, just a sec.
No. How did you get that?
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\[\int\limits x^{1/2}dx = \frac{2}{3}x^{3/2}+C.\]
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