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Mathematics 28 Online
OpenStudy (cwrw238):

Find f' in terms of g' if f(x) = g(x + g(a)).

OpenStudy (agent47):

is a a constant?

OpenStudy (cwrw238):

yes

OpenStudy (agent47):

f'(x)=g'(x+g(a))*(1+0)=g'(x+g(a))

OpenStudy (agent47):

unless I'm doing something wrong.

OpenStudy (cwrw238):

i'm studying calculus at the moment i have a mental block with this one.

OpenStudy (agent47):

lol this is one of those questions that looks too easy to be true, but I think that is the answer.

OpenStudy (agent47):

if a is a constant, g(a) is a constant, so when you differentiate g(x+g(a)), then you just have the derivative of g: g'(x+g(a)), multiplied by the derivative of the inside, but: x'=1 g(a)=0, since g(a) is a constant, so all you have left is: g'(x+g(a))

OpenStudy (cwrw238):

yes derivaivte of x is 1 and that of a constant is 0 so it seems right...

OpenStudy (cwrw238):

lol! - like that one

OpenStudy (cwrw238):

as you say its easy - just use chain rule ty

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