Question

the change in x = vi x the change in t + 1/2a times the change in t squared. solve for a.

Answer 1

\[\Delta x = vi \times \Delta t + {1 \over 2}a \times \Delta t^2\]The question doesn't make sense. Differentiation?

Answer 2

modern phyics algebra review s - solving for a variable
You have in typed correctly if you take out the multiplication signs.

Answer 3

Can you tell me how you managed to type in the difference or delta symbol? That would help me type the problem in better. Thanks.

Answer 4

I think he's simply saying:
\[
\Delta x= v_i\Delta t+\frac{1}{2}a(\Delta t)^2
\]And you can use the equation editor or use brackets to express in \(\LaTeX\) whatever you wish.

Answer 5

I don't know what the equation editor is.

Answer 6

Solving for \(a\) is:
\[\begin{align}
\Delta x-v_i\Delta t&= \frac{1}{2}a(\Delta t)^2\implies\\
2\Delta x-2v_i\Delta t&= a(\Delta t)^2\implies\\
\frac{2\Delta x-2v_i\Delta t}{(\Delta t)^2}&=a
\end{align}
\]

Answer 7

The equation editor is at the bottom left-hand corner of the textbox for the answers.

Answer 8

vf = vi + a times the change in t. solve for vi.