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OpenStudy (anonymous):
gymnast jumps straight up, with her center of mass moving at 3.57 m/s as she leaves the ground. How high above this point is her center of mass at the following times? (Ignore the effects of air resistance, and assume the initial height of her center of mass is at y = 0.) t (s) y (m) 0.100 ? 0.200 ? 0.300 ? 0.500 ?
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OpenStudy (anonymous):
You have a rate of 3.57 meters per second. The time is measured in tenths of a second. So, change the rate into meters per tenth of a second. \[\frac{ 3.57m }{ 1s }\]
OpenStudy (anonymous):
So, if she jumps 3.57 meters in one second, how many meters does she jump in a tenth of that time? You have to divide the meters by the same amount you divided the seconds.
OpenStudy (anonymous):
i got it already...i appreciate your help
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