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if the length of the hypotenuse of a right triangle is 10, find the length of the other sides when the area is a maximum. ans. 5sqr. 2 x 5sqr. 2
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u doin calculus?
Yes.
|dw:1347161748334:dw|
u need to find x such that area is maximim
Am i going to substitute it atthe eqn 1/2 x (sqrt (100-x^2) ?
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right area\(=f(x)=\frac{1}{2}x \sqrt{100-x^2} \)
easily u can see 0<x<10 so differentiate f(x) and find the x (solving f'(x)=0 ) for which area is max
Thanks :)
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