I'll post this underneath so it makes more sense! (:
\[(\frac{ 1 }{ 2 } + \frac{ \sqrt{3} }{ 2 }i)^2\]
I need to put it into standard form
And somehow I got the same answer, but not squared. :c
please show your steps so that I can help spot where you may have made a mistake
Oh heck, there are a lot of steps. Lool. This might be a while.
please use the draw facility if that makes it any easier
\[= (\frac{ 1 }{ 2 } + \frac{ \sqrt{3} }{ 2 } i)(\frac{ 1 }{ 2 } + \frac{ \sqrt{3} }{ 2 } i) \] \[\frac{ 1 }{ 2 }(\frac{ 1 }{ 2 } + \frac{ \sqrt{3} }{ 2 } i) + \frac{ \sqrt{3} }{ 2 }i(\frac{ 1 }{ 2 } + \frac{ \sqrt{3} }{ 2 } i) \]
Imma still going.
ok... :)
\[\frac{ 1 }{ 4 } + \frac{ \sqrt{3} }{ 4 } i +\frac{ \sqrt{3} }{ 4 } i +\frac{ 3 }{ 4 } i^2\] \[\frac{ 1 }{ 4 } +\frac{ \sqrt{3} }{ 2 } i + \frac{ 3 }{ 4 } i^2\]
That last step is where I think I messed up
all correct so far :)
now do you know what \(i^2=?\)
\[\frac{ 1 }{ 4 } + \frac{ \sqrt{3} }{ 2 }i -\frac{ 3 }{ 4 }\]
perfect! now just one more step left...
\[\frac{ 1 }{ 2 } + \frac{ \sqrt{3} }{ 2 } i\]
not quite:\[\frac{1}{4}-\frac{3}{4}\ne\frac{1}{2}\]
1 - 3 = ?
-2
do you see where you went wrong now?
LOL. I always mess up at the end. Thank you so much. (:
yw :) - at least you pursued this to the end - which means you learnt something from it! :D
Veery true! (:
:)
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