Question

If f(x)=3+5/x, which of the following CANNOT be value of f(x)?

-5/3


-3/5


0


5/3


3

Answer 1

so wich one when put on y,gives x as 0

Answer 2

remember hyperbola horizontal asymptote

Answer 3

0, because you can't divide by 0.

Answer 4

no

Answer 5

that will be correct if they where looking for x-value

Answer 6

y=3 is the HA-horizontal asymtote

Answer 7

if 5/x = -3 then f(x) = 0 so its not this option

Answer 8

try equating
eg 3 + 5/x = -5/3
5/x = - -14/3
-14x = 15

- so it can't be first choice -5/3

Answer 9

3 is correct choice

3 + 5/x = 3
5/x = 0
x x = 5/0 which is indeterminate

Answer 10

x=15/-14 is a legitimate answer, so -5/3 can be a value of x.

Answer 11

* x = 5/0

Answer 12

yes -5/3 can be a value of f(x)

Answer 13

@cwrw238 u can never divide by 0 though

Answer 14

division by 0 can never be done
5 /0 is meaningless
- no matter how many 0;s you add together the sum will be zero - never 5

Answer 15

correct answer is 3
f(x) = 3 + 5/x can never have a value 3