Question

How do I solve this:

x-x^3=2

Answer 1

\[x-x^3 = x(1-x^2)\]

Answer 2

therefore either x=2 or 1-x^2=2

Answer 3

say \[x \neq, then 1-x^2=2\]

Answer 4

\[1-x^2=2, will give x^2=-1, which has complex roots \therefore only answer is x=2\]

Answer 5

Well two doesnt work out. The real answer is -1.52
Is their any way to do this algebraically?

Answer 6

can you retype the question,please

Answer 7

Sure, \[x - x ^{3} =2 \]

Answer 8

just to make sure it is x^3, right?

Answer 9

Yeah its x cubed

Answer 10

and are you familiar with complex numbers

Answer 11

sorry for asking

Answer 12

We've done last year but im not sure Ill remember.
Im not even sure if I have to figure this out alebraically.
So Ill just ask a friend tommorow.
But thanks alot fo helping.

Answer 13

i think you take the magnitude of the real and imaginary solution you will have the answer as -1.5, which makes complete sense

Answer 14

else this equation cant have real roots

Answer 15

Oh wow that makes sense, I think ive got it from here. Thanks again!!