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OpenStudy (anonymous):
\[x-x^3 = x(1-x^2)\]
OpenStudy (anonymous):
therefore either x=2 or 1-x^2=2
OpenStudy (anonymous):
say \[x \neq, then 1-x^2=2\]
OpenStudy (anonymous):
\[1-x^2=2, will give x^2=-1, which has complex roots \therefore only answer is x=2\]
OpenStudy (anonymous):
Well two doesnt work out. The real answer is -1.52
Is their any way to do this algebraically?
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OpenStudy (anonymous):
can you retype the question,please
OpenStudy (anonymous):
Sure, \[x - x ^{3} =2 \]
OpenStudy (anonymous):
just to make sure it is x^3, right?
OpenStudy (anonymous):
Yeah its x cubed
OpenStudy (anonymous):
and are you familiar with complex numbers
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OpenStudy (anonymous):
sorry for asking
OpenStudy (anonymous):
We've done last year but im not sure Ill remember.
Im not even sure if I have to figure this out alebraically.
So Ill just ask a friend tommorow.
But thanks alot fo helping.
OpenStudy (anonymous):
i think you take the magnitude of the real and imaginary solution you will have the answer as -1.5, which makes complete sense
OpenStudy (anonymous):
else this equation cant have real roots
OpenStudy (anonymous):
Oh wow that makes sense, I think ive got it from here. Thanks again!!