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Physics 21 Online
OpenStudy (anonymous):

A projectile is fired straight up at a speed of 10 m/s. How long does it take to reach the top of its motion? The acceleration due to gravity is 9.8 m/s^2. Answer in units of s.

OpenStudy (anonymous):

have you tried what he suggested which is using the equation vfinal = vinitial + acceleration * change in time?

OpenStudy (anonymous):

then solve for t final

OpenStudy (anonymous):

isn't this time of flight as opposed to time to reach its maximum height?

OpenStudy (anonymous):

the question asks when it reaches the top of its motion, which we can say v final is zero

OpenStudy (anonymous):

got it! :)

OpenStudy (anonymous):

Why do I get -1.02 as a result? I used 0=10+9.8t. The time shouldn't be negative, right?

OpenStudy (anonymous):

The projectile is decelerating at a rate of 9.8 when it's thrown upward, so a=-9.8.

OpenStudy (anonymous):

and your time should now be positive

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