Question

Grace is three years younger than her sister Jane. Twice the sum of their ages is 4 more than their father's age. if their father is 54, find the ages of Grace and Jane. (How do I start?)

Answer 1

g = j -3

2(j+g)-4 = 54

can you solve this?

Answer 2

it becomes j + g = 25

Answer 3

Sorry I'm lost. Can you go step by step with me please?

Answer 4

ok g = grace, j = jill
grace is 3 years younger than her sister

so if you take grace and add 3 to it you get her sisters age

g+3 = j

so g = j -3

ok?

Answer 5

@zzr0ck3r how u will find the value of g or j

Answer 6

as it becomes g = 25 - j
or j = 25 - g

Answer 7

Okay I get it. Thanks everyone!

Answer 8

twice the sum of there ages is 4 more than ther fathers

so twice there ages added together equals there fathers age + 4

2(g+j) = 54+4

so we have g - j = -3 and 2g+2j = 58 or g+j = 24

g-j = -3
g+j = 29

add the two equations

2g = 26

g = 13

13+j = 29

j = 16

Answer 9

make sense @Ekaansh ?

Answer 10

k
i forgot about the second eq.
now we can solve it by any method :)

Answer 11

word

Answer 12

[(j-3) + g] 2 - 4 = 54 ?

Answer 13

what is your queston @li_za12 ?

Answer 14

is that right?

Answer 15

you cant solve 2 variables in one equation. but yes this would work for one equation, its the same thing I did.

Answer 16

Let the age of grace be \(x\).then
his sister's age=\(x+3\)

A/q,
\(2(x+(x+3))=54+4\)
\(2(x+(x+3))=58\)
solve this & gt ur answers :)