Give the value of x where the function f(x)=(x^2-2x+1)/(x^2-1) has a removable discontinuity.
These discontinuity problems are giving me a lot of trouble.
I mean, I'm pretty sure I need to factor it out, which I've done. I end up with [(x-1)(x-1)]/[(x+1)(x-1)]. Then, after cancelling out (x-1) in the numerator and the denominator, I'm left with (x-1)/(x+1). But how do I use this information to determine what value of x will result in a removable discontinuity?
Thanks, I'm just hoping to learn the more precise way.
Well the values for which the function is undefined is when the denominator = 0 So x=/=-1
So I just read this. In the original function, if you plug in x=1 or x=-1, then it is undefined. The difference is that after you simplify it, plugging in a removable x will yield a nonzero answer
Meaning that your x=1 is removable
The answer is actually 1. I'm just trying to figure out how they arrived at that answer.
Ohh, lemme read that again.
Sorry its not very nicely phrased. you can look up the website I was reading off: http://integralcalc.com/removable-discontinuity-example-1/
Thanks, that vid is pretty helpful.
Np I learnt something new too
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