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Mathematics 23 Online
OpenStudy (anonymous):

Prove.

OpenStudy (lgbasallote):

the meaning of life?

OpenStudy (jiteshmeghwal9):

LOL;

OpenStudy (anonymous):

\[\frac{\tan(x)}{\tan(y)}=\frac{\tan(x)+\cot(y)}{\cot(y)+\tan(x)} \] and find restrictions on x and y

OpenStudy (anonymous):

TYPING !!!

OpenStudy (lgbasallote):

tan/tan?

OpenStudy (lgbasallote):

nice

OpenStudy (anonymous):

is it only I or everyone of u getting right side = 1 ??

OpenStudy (lgbasallote):

\[\huge \frac{\tan x + \cot y}{\cot x + \tan y} \implies \frac{\frac{\sin x}{\cos x} + \frac{\cos y}{\sin y} }{\frac{\cos x}{\sin x} + \frac{\sin y}{\cos y}}\] that should get you started

OpenStudy (anonymous):

i think the denominator is tan y + cot x ....

OpenStudy (lgbasallote):

hmmm....

OpenStudy (lgbasallote):

either i made a typo... or @powerangers69 made a typo..

OpenStudy (anonymous):

then u need to write cot y = 1/ tan y cot x = 1/ tan x no need to convert into sin and cos.......

OpenStudy (anonymous):

yeah i did that .. just trying to find what the resitrctions are on x and y

OpenStudy (anonymous):

x and y can't be multiples of pi/2

OpenStudy (anonymous):

i got cotx+tany=/=0,tany=/=0,tanx=/=0

OpenStudy (anonymous):

they cant be 0 either? or division by 0

OpenStudy (anonymous):

yup, can't be 0 or multiples of 2pi

OpenStudy (anonymous):

cotx+tany=/= as well yeah

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