Question

.

Answer 1

im sorry i meant the 0 is θ

Answer 2

why the +pi ? to swing it to the 2nd quad ok

Answer 3

knowing the "r" value, we could have done arccos (x/r) as well

Answer 4

I added it because x < 0

Answer 5

-1/6 will give out a negative answer

Answer 6

you work look fine to me

Answer 7

so my answer is correct?

Answer 8

yes; the polar form is a radius of sqrt(37) at about a 2.9 radian measure

Answer 9

or .... i have to wonder a little about the angle at the moment

Answer 10

ok

Answer 11

we dont want to put it in the second quadrant do we?

Answer 12

2pi + arctan(-1/6) sounds better to me

Answer 13

ok

Answer 14

we have a -0.165 radian; which is equivalent to 2pi - 0.165 to fit it between 0 adn 2pi

Answer 15

trying to define it in the 2nd quadrant is just a bad idea :) we dont want to move it from where it is at, we just want to define it

Answer 16

so the radian is 2.9?

Answer 17

http://www.wolframalpha.com/input/?i=2pi+%2B+tan%5E-1%28-1%2F6%29

im going with more like; 6.12

Answer 18

ok