Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

find the limit as x approaches 0 of sin5x/sin4x

OpenStudy (anonymous):

u know x--->0 sinx/x =1

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

so use f(x)---->0 sin(f(x) )/ (f(x)) =1

OpenStudy (anonymous):

so x----->0 sin(5x) / (5x) =1

OpenStudy (anonymous):

and x----->0 sin(4x) / (4x) =1

OpenStudy (anonymous):

yes i got that far and then

OpenStudy (anonymous):

x approaches 0 of (sin5x/5x) / (sin4x/4x) * (5/4)

OpenStudy (anonymous):

I believe you can also use L'Hopital's rule on this. Just take f'(x)/g'(x) and your limit should go to 5/4 since cos(5x) and cos(4x) both go to 1 as x--->0

OpenStudy (anonymous):

ok thank you both I got that answer but I wasn't sure if it was right. =)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!