Question

Help please

Answer 1

start by simplifying each part, ex: \[6\sqrt{2x^2}=6x \sqrt{2}\]

Answer 2

ok, next?

Answer 3

do the next to parts and tell me what u got

Answer 4

\[6x \sqrt{2}-3x \sqrt{12}-2x^2\sqrt{8}\]

Answer 5

?

Answer 6

\[3\sqrt{12x}= 6\sqrt{3x}\]

Answer 7

ok

Answer 8

you need to redo the last one too

Answer 9

i wasnt sure how to do that one because it had x^2

Answer 10

u just pull out an x

Answer 11

\[-2x \sqrt{8x}\]?

Answer 12

yes but the 8 can be reduced too

Answer 13

4?

Answer 14

\[-2x \sqrt{4x}\]?