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How do you find the limit of x as it approaches c of 2x^3-3x^2+x-1
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meant that as x approaches c
replace \(x\) by \(c\)
any polynomial (like what you have) is continuous, meaning the limit of the function is equal to the value of the function. in other words, you can replace \(x\) by whatever number you want, and get not only the value of the function but also the limit
that's all I would do? so it'd be 2c^3 - 3c^2 + c -1?
yes
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thanks! guess I'm just overcomplicating it, tried factoring it somehow, everything
nope, just plug in yw
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