Question

\[7\sqrt{27/50}-3\sqrt{2/3}\]

Answer 1

where are you stuck?

Answer 2

I'm really not sure where to begin with this. Do I start by reducing the values in the radicals?

Answer 3

yes

Answer 4

Is there even a common value between 27 and 50? Should I reduce them as their own radical, i.e. \[\sqrt{27} \sqrt{50}\]?

Answer 5

find a factor

Answer 6

factor out 27 and factor out 50

Answer 7

can you think of a perfect square that fits in 27?

Answer 8

3 cubed

Answer 9

find a perfect square that you can divide 27 with...not cube

Answer 10

I'm not sure I understand how 3 or 9 goes into 50

Answer 11

stop thinking about 50

Answer 12

am I treating 27/50 as a fraction?

Answer 13

you're not going to turn this into simple terms

Answer 14

the plan is to extract the roots of 27 and 50 SEPARATELY

Answer 15

so \[\sqrt{27} = \sqrt{9 \times 3}\]
what is sqrt of 9?

Answer 16

3

Answer 17

right. so \(\sqrt{27} \implies 3\sqrt 3\)

agree?

Answer 18

Should I reduce them as their own radical, i.e.
27−−√50−−√

Answer 19

thats what I asked before and I was told no

Answer 20

who said no?

Answer 21

\[3\sqrt{3} and 5\sqrt{2}\]

Answer 22

right so... \[\frac{\sqrt{27}}{\sqrt{50}} \implies \frac{3\sqrt 3}{5\sqrt 2}\]

Answer 23

whoever the person was that bowed out from helping, 4th post I asked and porsha9 said no, so anyway, back on track

Answer 24

anyways...you got what i just did?

Answer 25

yes, thanks. so now do I multiply that by its conjugate? to remove the radical in the denominator

Answer 26

no... multiply it to 7...because you originally had \[7 \sqrt{\frac{27}{50}}\]
we just solved sqrt (27/50)

Answer 27

so... \[\frac{ 21\sqrt{3} }{ 35\sqrt{2} }\] ?

Answer 28

no...you don't multiply 7 to the denominator

Answer 29

just the numerator

Answer 30

Thanks for the help, it's getting late and I'm just going to stop at the learning assistance center tomorrow to work with someone on it. Thanks again.

Answer 31

welcome